133534045041151 has 4 divisors (see below), whose sum is σ = 134107152530832. Its totient is φ = 132960937551472.

The previous prime is 133534045041149. The next prime is 133534045041223. The reversal of 133534045041151 is 151140540435331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133534045041151 - 2¹ = 133534045041149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133534045041251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 286553744491 + ... + 286553744956.

It is an arithmetic number, because the mean of its divisors is an integer number (33526788132708).

Almost surely, 2^{133534045041151} is an apocalyptic number.

133534045041151 is a deficient number, since it is larger than the sum of its proper divisors (573107489681).

133534045041151 is an equidigital number, since it uses as much as digits as its factorization.

133534045041151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 573107489680.

The product of its (nonzero) digits is 216000, while the sum is 40.

Adding to 133534045041151 its reverse (151140540435331), we get a palindrome (284674585476482).

The spelling of 133534045041151 in words is "one hundred thirty-three trillion, five hundred thirty-four billion, forty-five million, forty-one thousand, one hundred fifty-one".