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133534045041223 is a prime number
BaseRepresentation
bin11110010111001011010001…
…010100011111001001000111
3122111210201201012020120020011
4132113023101110133021013
5120000310211012304343
61152000405440051051
740061342056003201
oct3627132124371107
9574721635216204
10133534045041223
113960351a222802
1212b87961603a87
13596828b659958
1424d9121a3d771
1510687d871a29d
hex7972d151f247

133534045041223 has 2 divisors, whose sum is σ = 133534045041224. Its totient is φ = 133534045041222.

The previous prime is 133534045041149. The next prime is 133534045041227. The reversal of 133534045041223 is 322140540435331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133534045041223 - 217 = 133534044910151 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133534045041227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66767022520611 + 66767022520612.

It is an arithmetic number, because the mean of its divisors is an integer number (66767022520612).

Almost surely, 2133534045041223 is an apocalyptic number.

133534045041223 is a deficient number, since it is larger than the sum of its proper divisors (1).

133534045041223 is an equidigital number, since it uses as much as digits as its factorization.

133534045041223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 133534045041223 its reverse (322140540435331), we get a palindrome (455674585476554).

The spelling of 133534045041223 in words is "one hundred thirty-three trillion, five hundred thirty-four billion, forty-five million, forty-one thousand, two hundred twenty-three".