13353443450051 has 2 divisors, whose sum is σ = 13353443450052. Its totient is φ = 13353443450050.

The previous prime is 13353443449987. The next prime is 13353443450093. The reversal of 13353443450051 is 15005434435331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13353443450051 - 2⁶ = 13353443449987 is a prime.

It is a super-3 number, since 3×13353443450051³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13353443449990 and 13353443450008.

It is not a weakly prime, because it can be changed into another prime (13353443450551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676721725025 + 6676721725026.

It is an arithmetic number, because the mean of its divisors is an integer number (6676721725026).

Almost surely, 2^{13353443450051} is an apocalyptic number.

13353443450051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13353443450051 is an equidigital number, since it uses as much as digits as its factorization.

13353443450051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648000, while the sum is 41.

Adding to 13353443450051 its reverse (15005434435331), we get a palindrome (28358877885382).

The spelling of 13353443450051 in words is "thirteen trillion, three hundred fifty-three billion, four hundred forty-three million, four hundred fifty thousand, fifty-one".