Base | Representation |
---|---|
bin | 1100001001010001011101… |
… | …0000001101111010000001 |
3 | 1202021120120102201010201001 |
4 | 3002110113100031322001 |
5 | 3222240323010403442 |
6 | 44222253124212001 |
7 | 2545516530353053 |
oct | 302242720157201 |
9 | 52246512633631 |
10 | 13353443450497 |
11 | 42891887823a7 |
12 | 15b7ba123a001 |
13 | 75b2bba83ac7 |
14 | 34244ad358d3 |
15 | 182548b772b7 |
hex | c251740de81 |
13353443450497 has 2 divisors, whose sum is σ = 13353443450498. Its totient is φ = 13353443450496.
The previous prime is 13353443450407. The next prime is 13353443450551. The reversal of 13353443450497 is 79405434435331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9775383686721 + 3578059763776 = 3126561^2 + 1891576^2 .
It is a cyclic number.
It is not a de Polignac number, because 13353443450497 - 239 = 12803687636609 is a prime.
It is a super-3 number, since 3×133534434504973 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13353443450407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676721725248 + 6676721725249.
It is an arithmetic number, because the mean of its divisors is an integer number (6676721725249).
Almost surely, 213353443450497 is an apocalyptic number.
It is an amenable number.
13353443450497 is a deficient number, since it is larger than the sum of its proper divisors (1).
13353443450497 is an equidigital number, since it uses as much as digits as its factorization.
13353443450497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32659200, while the sum is 55.
The spelling of 13353443450497 in words is "thirteen trillion, three hundred fifty-three billion, four hundred forty-three million, four hundred fifty thousand, four hundred ninety-seven".
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