Base | Representation |
---|---|
bin | 1100001001010001011101… |
… | …0000001101111010110001 |
3 | 1202021120120102201010202211 |
4 | 3002110113100031322301 |
5 | 3222240323010404140 |
6 | 44222253124212121 |
7 | 2545516530353152 |
oct | 302242720157261 |
9 | 52246512633684 |
10 | 13353443450545 |
11 | 4289188782440 |
12 | 15b7ba123a041 |
13 | 75b2bba83b33 |
14 | 34244ad35929 |
15 | 182548b772ea |
hex | c251740deb1 |
13353443450545 has 32 divisors (see below), whose sum is σ = 17588971100160. Its totient is φ = 9651635808000.
The previous prime is 13353443450497. The next prime is 13353443450551. The reversal of 13353443450545 is 54505434435331.
It is not a de Polignac number, because 13353443450545 - 229 = 13352906579633 is a prime.
It is a super-3 number, since 3×133534434505453 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10546771 + ... + 11744839.
It is an arithmetic number, because the mean of its divisors is an integer number (549655346880).
Almost surely, 213353443450545 is an apocalyptic number.
It is an amenable number.
13353443450545 is a deficient number, since it is larger than the sum of its proper divisors (4235527649615).
13353443450545 is a wasteful number, since it uses less digits than its factorization.
13353443450545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1199337.
The product of its (nonzero) digits is 12960000, while the sum is 49.
Adding to 13353443450545 its reverse (54505434435331), we get a palindrome (67858877885876).
The spelling of 13353443450545 in words is "thirteen trillion, three hundred fifty-three billion, four hundred forty-three million, four hundred fifty thousand, five hundred forty-five".
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