Base | Representation |
---|---|
bin | 1100001001010001011101… |
… | …0010010101010111010101 |
3 | 1202021120120110202022210112 |
4 | 3002110113102111113111 |
5 | 3222240323131132313 |
6 | 44222253144132405 |
7 | 2545516535153465 |
oct | 302242722252725 |
9 | 52246513668715 |
10 | 13353444005333 |
11 | 4289189021243 |
12 | 15b7ba1467105 |
13 | 75b2bbc19503 |
14 | 34244b03bba5 |
15 | 182548c368a8 |
hex | c25174955d5 |
13353444005333 has 8 divisors (see below), whose sum is σ = 14077678308288. Its totient is φ = 12641180517504.
The previous prime is 13353444005273. The next prime is 13353444005357. The reversal of 13353444005333 is 33350044435331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13353444005333 - 230 = 13352370263509 is a prime.
It is a super-3 number, since 3×133534440053333 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13353444005633) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2992701491 + ... + 2992705952.
It is an arithmetic number, because the mean of its divisors is an integer number (1759709788536).
Almost surely, 213353444005333 is an apocalyptic number.
It is an amenable number.
13353444005333 is a deficient number, since it is larger than the sum of its proper divisors (724234302955).
13353444005333 is an equidigital number, since it uses as much as digits as its factorization.
13353444005333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5985407563.
The product of its (nonzero) digits is 1166400, while the sum is 41.
The spelling of 13353444005333 in words is "thirteen trillion, three hundred fifty-three billion, four hundred forty-four million, five thousand, three hundred thirty-three".
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