Base | Representation |
---|---|
bin | 1100001001010001101010… |
… | …1001001001000111101011 |
3 | 1202021120201101201012200221 |
4 | 3002110122221021013223 |
5 | 3222240432040104024 |
6 | 44222302515110511 |
7 | 2545521120614104 |
oct | 302243251110753 |
9 | 52246641635627 |
10 | 13353500316139 |
11 | 42892078923a5 |
12 | 15b7bb82a2437 |
13 | 75b2ca7a4209 |
14 | 3424546d93ab |
15 | 18254db5b3e4 |
hex | c251aa491eb |
13353500316139 has 2 divisors, whose sum is σ = 13353500316140. Its totient is φ = 13353500316138.
The previous prime is 13353500316077. The next prime is 13353500316157. The reversal of 13353500316139 is 93161300535331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13353500316139 - 29 = 13353500315627 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13353500316095 and 13353500316104.
It is not a weakly prime, because it can be changed into another prime (13353500317139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676750158069 + 6676750158070.
It is an arithmetic number, because the mean of its divisors is an integer number (6676750158070).
Almost surely, 213353500316139 is an apocalyptic number.
13353500316139 is a deficient number, since it is larger than the sum of its proper divisors (1).
13353500316139 is an equidigital number, since it uses as much as digits as its factorization.
13353500316139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 328050, while the sum is 43.
The spelling of 13353500316139 in words is "thirteen trillion, three hundred fifty-three billion, five hundred million, three hundred sixteen thousand, one hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •