Base | Representation |
---|---|
bin | 1100001001010011101100… |
… | …0111100010010011111010 |
3 | 1202021122010100220212111111 |
4 | 3002110323013202103322 |
5 | 3222243041024421204 |
6 | 44222432540550534 |
7 | 2545540454640226 |
oct | 302247307422372 |
9 | 52248110825444 |
10 | 13354045154554 |
11 | 4289467394585 |
12 | 15b812a85244a |
13 | 75b386628200 |
14 | 3424a6c03786 |
15 | 1825818ced04 |
hex | c253b1e24fa |
13354045154554 has 24 divisors (see below), whose sum is σ = 21691273547520. Its totient is φ = 6163170341328.
The previous prime is 13354045154551. The next prime is 13354045154591. The reversal of 13354045154554 is 45545154045331.
13354045154554 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13354045154498 and 13354045154507.
It is not an unprimeable number, because it can be changed into a prime (13354045154551) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8279977 + ... + 9760435.
It is an arithmetic number, because the mean of its divisors is an integer number (903803064480).
Almost surely, 213354045154554 is an apocalyptic number.
13354045154554 is a deficient number, since it is larger than the sum of its proper divisors (8337228392966).
13354045154554 is a wasteful number, since it uses less digits than its factorization.
13354045154554 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1507174 (or 1507161 counting only the distinct ones).
The product of its (nonzero) digits is 7200000, while the sum is 49.
Adding to 13354045154554 its reverse (45545154045331), we get a palindrome (58899199199885).
The spelling of 13354045154554 in words is "thirteen trillion, three hundred fifty-four billion, forty-five million, one hundred fifty-four thousand, five hundred fifty-four".
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