1335411305113 has 2 divisors, whose sum is σ = 1335411305114. Its totient is φ = 1335411305112.

The previous prime is 1335411305083. The next prime is 1335411305159. The reversal of 1335411305113 is 3115031145331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1329621160464 + 5790144649 = 1153092^2 + 76093^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1335411305113 is a prime.

It is a super-3 number, since 3×1335411305113³ (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1335411305183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667705652556 + 667705652557.

It is an arithmetic number, because the mean of its divisors is an integer number (667705652557).

Almost surely, 2^{1335411305113} is an apocalyptic number.

It is an amenable number.

1335411305113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1335411305113 is an equidigital number, since it uses as much as digits as its factorization.

1335411305113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100, while the sum is 31.

The spelling of 1335411305113 in words is "one trillion, three hundred thirty-five billion, four hundred eleven million, three hundred five thousand, one hundred thirteen".