Base | Representation |
---|---|
bin | 11110010111010011110011… |
… | …100110100101011010100001 |
3 | 122111211121100221000002122112 |
4 | 132113103303212211122201 |
5 | 120000432443244123231 |
6 | 1152004523120045105 |
7 | 40062115145052515 |
oct | 3627236346453241 |
9 | 574747327002575 |
10 | 133543210145441 |
11 | 396073a27321a8 |
12 | 12b8969aa63795 |
13 | 59690bc396a45 |
14 | 24d9750d52145 |
15 | 1068b7315b92b |
hex | 7974f39a56a1 |
133543210145441 has 2 divisors, whose sum is σ = 133543210145442. Its totient is φ = 133543210145440.
The previous prime is 133543210145437. The next prime is 133543210145447. The reversal of 133543210145441 is 144541012345331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 87004494864400 + 46538715281041 = 9327620^2 + 6821929^2 .
It is a cyclic number.
It is not a de Polignac number, because 133543210145441 - 22 = 133543210145437 is a prime.
It is not a weakly prime, because it can be changed into another prime (133543210145447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66771605072720 + 66771605072721.
It is an arithmetic number, because the mean of its divisors is an integer number (66771605072721).
Almost surely, 2133543210145441 is an apocalyptic number.
It is an amenable number.
133543210145441 is a deficient number, since it is larger than the sum of its proper divisors (1).
133543210145441 is an equidigital number, since it uses as much as digits as its factorization.
133543210145441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 41.
The spelling of 133543210145441 in words is "one hundred thirty-three trillion, five hundred forty-three billion, two hundred ten million, one hundred forty-five thousand, four hundred forty-one".
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