Base | Representation |
---|---|
bin | 1100001001010101001011… |
… | …1001100101010110011011 |
3 | 1202021200011011200221120221 |
4 | 3002111102321211112123 |
5 | 3222244400200301141 |
6 | 44222540312500511 |
7 | 2545553401226605 |
oct | 302252271452633 |
9 | 52250134627527 |
10 | 13354444150171 |
11 | 4289651633923 |
12 | 15b82203aa737 |
13 | 75b41b1a75a7 |
14 | 342503bc6175 |
15 | 1825a6945bd1 |
hex | c2552e6559b |
13354444150171 has 2 divisors, whose sum is σ = 13354444150172. Its totient is φ = 13354444150170.
The previous prime is 13354444150141. The next prime is 13354444150237. The reversal of 13354444150171 is 17105144445331.
13354444150171 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13354444150171 - 27 = 13354444150043 is a prime.
It is not a weakly prime, because it can be changed into another prime (13354444150141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6677222075085 + 6677222075086.
It is an arithmetic number, because the mean of its divisors is an integer number (6677222075086).
Almost surely, 213354444150171 is an apocalyptic number.
13354444150171 is a deficient number, since it is larger than the sum of its proper divisors (1).
13354444150171 is an equidigital number, since it uses as much as digits as its factorization.
13354444150171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 403200, while the sum is 43.
The spelling of 13354444150171 in words is "thirteen trillion, three hundred fifty-four billion, four hundred forty-four million, one hundred fifty thousand, one hundred seventy-one".
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