Base | Representation |
---|---|
bin | 1100001001010111010000… |
… | …1101110110110000000111 |
3 | 1202021201121010111011200202 |
4 | 3002111310031312300013 |
5 | 3222302021244044310 |
6 | 44223112001201115 |
7 | 2545603266306344 |
oct | 302256415666007 |
9 | 52251533434622 |
10 | 13355003112455 |
11 | 4289909102524 |
12 | 15b835763019b |
13 | 75b4a9c351c4 |
14 | 3425581297cb |
15 | 1825daa593a5 |
hex | c2574376c07 |
13355003112455 has 4 divisors (see below), whose sum is σ = 16026003734952. Its totient is φ = 10684002489960.
The previous prime is 13355003112449. The next prime is 13355003112491. The reversal of 13355003112455 is 55421130055331.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13355003112455 - 230 = 13353929370631 is a prime.
It is a super-2 number, since 2×133550031124552 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335500311241 + ... + 1335500311250.
It is an arithmetic number, because the mean of its divisors is an integer number (4006500933738).
Almost surely, 213355003112455 is an apocalyptic number.
13355003112455 is a deficient number, since it is larger than the sum of its proper divisors (2671000622497).
13355003112455 is an equidigital number, since it uses as much as digits as its factorization.
13355003112455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2671000622496.
The product of its (nonzero) digits is 135000, while the sum is 38.
Adding to 13355003112455 its reverse (55421130055331), we get a palindrome (68776133167786).
The spelling of 13355003112455 in words is "thirteen trillion, three hundred fifty-five billion, three million, one hundred twelve thousand, four hundred fifty-five".
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