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13355003112455 = 52671000622491
BaseRepresentation
bin1100001001010111010000…
…1101110110110000000111
31202021201121010111011200202
43002111310031312300013
53222302021244044310
644223112001201115
72545603266306344
oct302256415666007
952251533434622
1013355003112455
114289909102524
1215b835763019b
1375b4a9c351c4
143425581297cb
151825daa593a5
hexc2574376c07

13355003112455 has 4 divisors (see below), whose sum is σ = 16026003734952. Its totient is φ = 10684002489960.

The previous prime is 13355003112449. The next prime is 13355003112491. The reversal of 13355003112455 is 55421130055331.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13355003112455 - 230 = 13353929370631 is a prime.

It is a super-2 number, since 2×133550031124552 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335500311241 + ... + 1335500311250.

It is an arithmetic number, because the mean of its divisors is an integer number (4006500933738).

Almost surely, 213355003112455 is an apocalyptic number.

13355003112455 is a deficient number, since it is larger than the sum of its proper divisors (2671000622497).

13355003112455 is an equidigital number, since it uses as much as digits as its factorization.

13355003112455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2671000622496.

The product of its (nonzero) digits is 135000, while the sum is 38.

Adding to 13355003112455 its reverse (55421130055331), we get a palindrome (68776133167786).

The spelling of 13355003112455 in words is "thirteen trillion, three hundred fifty-five billion, three million, one hundred twelve thousand, four hundred fifty-five".

Divisors: 1 5 2671000622491 13355003112455