Search a number
-
+
13355035040497 is a prime number
BaseRepresentation
bin1100001001010111011000…
…0111101001101011110001
31202021201200100120021201211
43002111312013221223301
53222302102432243442
644223115101400121
72545604134555123
oct302256607515361
952251610507654
1013355035040497
11428992512a537
1215b8366269041
1375b4b3733937
1434255c47b213
151825dd764617
hexc25761e9af1

13355035040497 has 2 divisors, whose sum is σ = 13355035040498. Its totient is φ = 13355035040496.

The previous prime is 13355035040437. The next prime is 13355035040563. The reversal of 13355035040497 is 79404053055331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6883282207201 + 6471752833296 = 2623601^2 + 2543964^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13355035040497 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13355035040497.

It is not a weakly prime, because it can be changed into another prime (13355035040437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6677517520248 + 6677517520249.

It is an arithmetic number, because the mean of its divisors is an integer number (6677517520249).

Almost surely, 213355035040497 is an apocalyptic number.

It is an amenable number.

13355035040497 is a deficient number, since it is larger than the sum of its proper divisors (1).

13355035040497 is an equidigital number, since it uses as much as digits as its factorization.

13355035040497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3402000, while the sum is 49.

The spelling of 13355035040497 in words is "thirteen trillion, three hundred fifty-five billion, thirty-five million, forty thousand, four hundred ninety-seven".