Base | Representation |
---|---|
bin | 111110001100001000… |
… | …0000001100011111001 |
3 | 110202201101110121110112 |
4 | 1330120100001203321 |
5 | 4142003003340212 |
6 | 141204041554105 |
7 | 12435341260505 |
oct | 1743020014371 |
9 | 422641417415 |
10 | 133550840057 |
11 | 51702a70898 |
12 | 21a71aa5935 |
13 | c794731a1b |
14 | 666ccdd305 |
15 | 3719964422 |
hex | 1f184018f9 |
133550840057 has 2 divisors, whose sum is σ = 133550840058. Its totient is φ = 133550840056.
The previous prime is 133550840047. The next prime is 133550840069. The reversal of 133550840057 is 750048055331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107607617296 + 25943222761 = 328036^2 + 161069^2 .
It is a cyclic number.
It is not a de Polignac number, because 133550840057 - 222 = 133546645753 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133550839996 and 133550840023.
It is not a weakly prime, because it can be changed into another prime (133550840047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66775420028 + 66775420029.
It is an arithmetic number, because the mean of its divisors is an integer number (66775420029).
Almost surely, 2133550840057 is an apocalyptic number.
It is an amenable number.
133550840057 is a deficient number, since it is larger than the sum of its proper divisors (1).
133550840057 is an equidigital number, since it uses as much as digits as its factorization.
133550840057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252000, while the sum is 41.
Adding to 133550840057 its reverse (750048055331), we get a palindrome (883598895388).
The spelling of 133550840057 in words is "one hundred thirty-three billion, five hundred fifty million, eight hundred forty thousand, fifty-seven".
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