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133554142993 is a prime number
BaseRepresentation
bin111110001100001110…
…0100111111100010001
3110202201121200102020111
41330120130213330101
54142004330033433
6141204240441321
712435411325165
oct1743034477421
9422647612214
10133554142993
1151704917397
1221a73019241
13c79531a21b
14666d51cca5
153719db7dcd
hex1f18727f11

133554142993 has 2 divisors, whose sum is σ = 133554142994. Its totient is φ = 133554142992.

The previous prime is 133554142979. The next prime is 133554143069. The reversal of 133554142993 is 399241455331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106229061184 + 27325081809 = 325928^2 + 165303^2 .

It is a cyclic number.

It is not a de Polignac number, because 133554142993 - 213 = 133554134801 is a prime.

It is a super-2 number, since 2×1335541429932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133554142913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66777071496 + 66777071497.

It is an arithmetic number, because the mean of its divisors is an integer number (66777071497).

Almost surely, 2133554142993 is an apocalyptic number.

It is an amenable number.

133554142993 is a deficient number, since it is larger than the sum of its proper divisors (1).

133554142993 is an equidigital number, since it uses as much as digits as its factorization.

133554142993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1749600, while the sum is 49.

The spelling of 133554142993 in words is "one hundred thirty-three billion, five hundred fifty-four million, one hundred forty-two thousand, nine hundred ninety-three".