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133560262242481 is a prime number
BaseRepresentation
bin11110010111100011101011…
…111111001011000010110001
3122111220020101022112101021011
4132113203223333023002301
5120001222404113224411
61152020423141430521
740063260543354244
oct3627435377130261
9574806338471234
10133560262242481
1139613653144088
1212b90a5970b441
13596a8a90caba9
1424da4cb91325b
1510693201c4c21
hex7978ebfcb0b1

133560262242481 has 2 divisors, whose sum is σ = 133560262242482. Its totient is φ = 133560262242480.

The previous prime is 133560262242461. The next prime is 133560262242497. The reversal of 133560262242481 is 184242262065331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121942526332081 + 11617735910400 = 11042759^2 + 3408480^2 .

It is a cyclic number.

It is not a de Polignac number, because 133560262242481 - 215 = 133560262209713 is a prime.

It is a super-2 number, since 2×1335602622424812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133560262242461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66780131121240 + 66780131121241.

It is an arithmetic number, because the mean of its divisors is an integer number (66780131121241).

Almost surely, 2133560262242481 is an apocalyptic number.

It is an amenable number.

133560262242481 is a deficient number, since it is larger than the sum of its proper divisors (1).

133560262242481 is an equidigital number, since it uses as much as digits as its factorization.

133560262242481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3317760, while the sum is 49.

The spelling of 133560262242481 in words is "one hundred thirty-three trillion, five hundred sixty billion, two hundred sixty-two million, two hundred forty-two thousand, four hundred eighty-one".