Search a number
-
+
1335605437643 is a prime number
BaseRepresentation
bin10011011011111000010…
…010011010010011001011
311201200102122021002110212
4103123320102122103023
5133340304443001033
62501322455431335
7165331355622131
oct23337022322313
94650378232425
101335605437643
114754774a5514
12196a2368554b
1398c4089ba39
1448902255751
1524b1ebe9748
hex136f849a4cb

1335605437643 has 2 divisors, whose sum is σ = 1335605437644. Its totient is φ = 1335605437642.

The previous prime is 1335605437603. The next prime is 1335605437667. The reversal of 1335605437643 is 3467345065331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1335605437643 - 214 = 1335605421259 is a prime.

It is a super-2 number, since 2×13356054376432 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 1335605437591 and 1335605437600.

It is not a weakly prime, because it can be changed into another prime (1335605437603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667802718821 + 667802718822.

It is an arithmetic number, because the mean of its divisors is an integer number (667802718822).

Almost surely, 21335605437643 is an apocalyptic number.

1335605437643 is a deficient number, since it is larger than the sum of its proper divisors (1).

1335605437643 is an equidigital number, since it uses as much as digits as its factorization.

1335605437643 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8164800, while the sum is 50.

The spelling of 1335605437643 in words is "one trillion, three hundred thirty-five billion, six hundred five million, four hundred thirty-seven thousand, six hundred forty-three".