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133565406064457 is a prime number
BaseRepresentation
bin11110010111101000011110…
…100101010010111101001001
3122111220201122210112121111012
4132113220132211102331021
5120001313422423030312
61152023033411413305
740063532163210623
oct3627503645227511
9574821583477435
10133565406064457
1139615852753724
1212b91a542b4235
13596b2189a4633
1424da858b31c13
151069521a8a322
hex797a1e952f49

133565406064457 has 2 divisors, whose sum is σ = 133565406064458. Its totient is φ = 133565406064456.

The previous prime is 133565406064217. The next prime is 133565406064487. The reversal of 133565406064457 is 754460604565331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78811977067321 + 54753428997136 = 8877611^2 + 7399556^2 .

It is a cyclic number.

It is not a de Polignac number, because 133565406064457 - 220 = 133565405015881 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133565406064396 and 133565406064405.

It is not a weakly prime, because it can be changed into another prime (133565406064487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66782703032228 + 66782703032229.

It is an arithmetic number, because the mean of its divisors is an integer number (66782703032229).

Almost surely, 2133565406064457 is an apocalyptic number.

It is an amenable number.

133565406064457 is a deficient number, since it is larger than the sum of its proper divisors (1).

133565406064457 is an equidigital number, since it uses as much as digits as its factorization.

133565406064457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108864000, while the sum is 59.

The spelling of 133565406064457 in words is "one hundred thirty-three trillion, five hundred sixty-five billion, four hundred six million, sixty-four thousand, four hundred fifty-seven".