Search a number
-
+
133610325633481 is a prime number
BaseRepresentation
bin11110011000010010010011…
…111111110110100111001001
3122112002000121022122010222211
4132120102103333312213021
5120003032421330232411
61152055423005545121
740100012265226354
oct3630222377664711
9575060538563884
10133610325633481
1139632903673794
1212b9a6ab8751a1
135972527034188
1424dcaba82529b
15106a7a03dc221
hex798493ff69c9

133610325633481 has 2 divisors, whose sum is σ = 133610325633482. Its totient is φ = 133610325633480.

The previous prime is 133610325633439. The next prime is 133610325633529. The reversal of 133610325633481 is 184336523016331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131604122509456 + 2006203124025 = 11471884^2 + 1416405^2 .

It is a cyclic number.

It is not a de Polignac number, because 133610325633481 - 29 = 133610325632969 is a prime.

It is a super-2 number, since 2×1336103256334812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133610325633431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66805162816740 + 66805162816741.

It is an arithmetic number, because the mean of its divisors is an integer number (66805162816741).

Almost surely, 2133610325633481 is an apocalyptic number.

It is an amenable number.

133610325633481 is a deficient number, since it is larger than the sum of its proper divisors (1).

133610325633481 is an equidigital number, since it uses as much as digits as its factorization.

133610325633481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2799360, while the sum is 49.

The spelling of 133610325633481 in words is "one hundred thirty-three trillion, six hundred ten billion, three hundred twenty-five million, six hundred thirty-three thousand, four hundred eighty-one".