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133640402605051 is a prime number
BaseRepresentation
bin11110011000101110010100…
…101110011001001111111011
3122112011220020102202121111211
4132120232110232121033323
5120004031021031330201
61152121315311503551
740102125521246206
oct3630562456311773
9575156212677454
10133640402605051
11396446382aa691
1212ba44a4527bb7
13597530b339084
14250033118893d
15106b460b6c651
hex798b94b993fb

133640402605051 has 2 divisors, whose sum is σ = 133640402605052. Its totient is φ = 133640402605050.

The previous prime is 133640402604977. The next prime is 133640402605057. The reversal of 133640402605051 is 150506204046331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133640402605051 - 29 = 133640402604539 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133640402604995 and 133640402605013.

It is not a weakly prime, because it can be changed into another prime (133640402605057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66820201302525 + 66820201302526.

It is an arithmetic number, because the mean of its divisors is an integer number (66820201302526).

Almost surely, 2133640402605051 is an apocalyptic number.

133640402605051 is a deficient number, since it is larger than the sum of its proper divisors (1).

133640402605051 is an equidigital number, since it uses as much as digits as its factorization.

133640402605051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 40.

The spelling of 133640402605051 in words is "one hundred thirty-three trillion, six hundred forty billion, four hundred two million, six hundred five thousand, fifty-one".