Base | Representation |
---|---|
bin | 11000111001001110… |
… | …11110001010111101 |
3 | 1021111102121220121100 |
4 | 30130213132022331 |
5 | 204332420324013 |
6 | 10050110323313 |
7 | 652124502015 |
oct | 143447361275 |
9 | 37442556540 |
10 | 13365011133 |
11 | 5739222751 |
12 | 270bab9539 |
13 | 134cbb2616 |
14 | 90b022c45 |
15 | 533503473 |
hex | 31c9de2bd |
13365011133 has 12 divisors (see below), whose sum is σ = 19715761728. Its totient is φ = 8720432520.
The previous prime is 13365011053. The next prime is 13365011161. The reversal of 13365011133 is 33111056331.
13365011133 is a `hidden beast` number, since 1 + 3 + 3 + 650 + 1 + 1 + 1 + 3 + 3 = 666.
It is not a de Polignac number, because 13365011133 - 224 = 13348233917 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13365011097 and 13365011106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13365011633) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 15797463 + ... + 15798308.
It is an arithmetic number, because the mean of its divisors is an integer number (1642980144).
Almost surely, 213365011133 is an apocalyptic number.
It is an amenable number.
13365011133 is a deficient number, since it is larger than the sum of its proper divisors (6350750595).
13365011133 is a wasteful number, since it uses less digits than its factorization.
13365011133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31595824 (or 31595821 counting only the distinct ones).
The product of its (nonzero) digits is 2430, while the sum is 27.
Adding to 13365011133 its reverse (33111056331), we get a palindrome (46476067464).
The spelling of 13365011133 in words is "thirteen billion, three hundred sixty-five million, eleven thousand, one hundred thirty-three".
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