Base | Representation |
---|---|
bin | 111110010000101100… |
… | …1001111011010000011 |
3 | 110210010002010200201201 |
4 | 1330201121033122003 |
5 | 4142311242013021 |
6 | 141231202042031 |
7 | 12442213244662 |
oct | 1744131173203 |
9 | 423102120651 |
10 | 133704251011 |
11 | 51781622801 |
12 | 21ab5349317 |
13 | c7ba456336 |
14 | 6685434dd9 |
15 | 3728169591 |
hex | 1f2164f683 |
133704251011 has 2 divisors, whose sum is σ = 133704251012. Its totient is φ = 133704251010.
The previous prime is 133704250991. The next prime is 133704251027. The reversal of 133704251011 is 110152407331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133704251011 is a prime.
It is not a weakly prime, because it can be changed into another prime (133704251071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66852125505 + 66852125506.
It is an arithmetic number, because the mean of its divisors is an integer number (66852125506).
Almost surely, 2133704251011 is an apocalyptic number.
133704251011 is a deficient number, since it is larger than the sum of its proper divisors (1).
133704251011 is an equidigital number, since it uses as much as digits as its factorization.
133704251011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2520, while the sum is 28.
Adding to 133704251011 its reverse (110152407331), we get a palindrome (243856658342).
The spelling of 133704251011 in words is "one hundred thirty-three billion, seven hundred four million, two hundred fifty-one thousand, eleven".
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