Base | Representation |
---|---|
bin | 11110011001111110011011… |
… | …111101101111100010110011 |
3 | 122112111010021101002112000111 |
4 | 132121332123331233202303 |
5 | 120011433203343234323 |
6 | 1152225023144202151 |
7 | 40111262302130401 |
oct | 3631763375574263 |
9 | 575433241075014 |
10 | 133726423414963 |
11 | 3967806a860325 |
12 | 12bb90b0769357 |
13 | 59804699448b2 |
14 | 25045717cc471 |
15 | 106d7e79d4c0d |
hex | 799f9bf6f8b3 |
133726423414963 has 2 divisors, whose sum is σ = 133726423414964. Its totient is φ = 133726423414962.
The previous prime is 133726423414921. The next prime is 133726423414967. The reversal of 133726423414963 is 369414324627331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133726423414963 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133726423414898 and 133726423414907.
It is not a weakly prime, because it can be changed into another prime (133726423414967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66863211707481 + 66863211707482.
It is an arithmetic number, because the mean of its divisors is an integer number (66863211707482).
Almost surely, 2133726423414963 is an apocalyptic number.
133726423414963 is a deficient number, since it is larger than the sum of its proper divisors (1).
133726423414963 is an equidigital number, since it uses as much as digits as its factorization.
133726423414963 is an evil number, because the sum of its binary digits is even.
The product of its digits is 47029248, while the sum is 58.
The spelling of 133726423414963 in words is "one hundred thirty-three trillion, seven hundred twenty-six billion, four hundred twenty-three million, four hundred fourteen thousand, nine hundred sixty-three".
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