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13373934841209 = 34457978280403
BaseRepresentation
bin1100001010011101110010…
…1000101010110101111001
31202100112110111212122021210
43002213130220222311321
53223104304304404314
644235522325553333
72550143400325665
oct302473450526571
952315414778253
1013373934841209
114296943618548
1215bbb5b875849
137602061bac77
143434325b18a5
15182d47b0a559
hexc29dca2ad79

13373934841209 has 4 divisors (see below), whose sum is σ = 17831913121616. Its totient is φ = 8915956560804.

The previous prime is 13373934841123. The next prime is 13373934841213. The reversal of 13373934841209 is 90214843937331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13373934841209 - 216 = 13373934775673 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13373934841249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2228989140199 + ... + 2228989140204.

It is an arithmetic number, because the mean of its divisors is an integer number (4457978280404).

Almost surely, 213373934841209 is an apocalyptic number.

It is an amenable number.

13373934841209 is a deficient number, since it is larger than the sum of its proper divisors (4457978280407).

13373934841209 is an equidigital number, since it uses as much as digits as its factorization.

13373934841209 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4457978280406.

The product of its (nonzero) digits is 11757312, while the sum is 57.

The spelling of 13373934841209 in words is "thirteen trillion, three hundred seventy-three billion, nine hundred thirty-four million, eight hundred forty-one thousand, two hundred nine".

Divisors: 1 3 4457978280403 13373934841209