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13373934841249 is a prime number
BaseRepresentation
bin1100001010011101110010…
…1000101010110110100001
31202100112110111212122100021
43002213130220222312201
53223104304304404444
644235522325553441
72550143400326053
oct302473450526641
952315414778307
1013373934841249
114296943618584
1215bbb5b875881
137602061baca8
143434325b18d3
15182d47b0a584
hexc29dca2ada1

13373934841249 has 2 divisors, whose sum is σ = 13373934841250. Its totient is φ = 13373934841248.

The previous prime is 13373934841213. The next prime is 13373934841261. The reversal of 13373934841249 is 94214843937331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12346614750625 + 1027320090624 = 3513775^2 + 1013568^2 .

It is a cyclic number.

It is not a de Polignac number, because 13373934841249 - 217 = 13373934710177 is a prime.

It is not a weakly prime, because it can be changed into another prime (13373934842249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6686967420624 + 6686967420625.

It is an arithmetic number, because the mean of its divisors is an integer number (6686967420625).

Almost surely, 213373934841249 is an apocalyptic number.

It is an amenable number.

13373934841249 is a deficient number, since it is larger than the sum of its proper divisors (1).

13373934841249 is an equidigital number, since it uses as much as digits as its factorization.

13373934841249 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 47029248, while the sum is 61.

The spelling of 13373934841249 in words is "thirteen trillion, three hundred seventy-three billion, nine hundred thirty-four million, eight hundred forty-one thousand, two hundred forty-nine".