13373934841213 has 2 divisors, whose sum is σ = 13373934841214. Its totient is φ = 13373934841212.

The previous prime is 13373934841123. The next prime is 13373934841249. The reversal of 13373934841213 is 31214843937331.

Together with previous prime (13373934841123) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7098318647289 + 6275616193924 = 2664267^2 + 2505118^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13373934841213 is a prime.

It is a super-2 number, since 2×13373934841213² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13373934841273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6686967420606 + 6686967420607.

It is an arithmetic number, because the mean of its divisors is an integer number (6686967420607).

Almost surely, 2^{13373934841213} is an apocalyptic number.

It is an amenable number.

13373934841213 is a deficient number, since it is larger than the sum of its proper divisors (1).

13373934841213 is an equidigital number, since it uses as much as digits as its factorization.

13373934841213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3919104, while the sum is 52.

The spelling of 13373934841213 in words is "thirteen trillion, three hundred seventy-three billion, nine hundred thirty-four million, eight hundred forty-one thousand, two hundred thirteen".