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1338394243 is a prime number
BaseRepresentation
bin100111111000110…
…0100011010000011
310110021102110202011
41033301210122003
510220112103433
6340450233351
745111110014
oct11761443203
93407373664
101338394243
1162754144a
12314285857
1318438b974
14c9a7700b
157c7763cd
hex4fc64683

1338394243 has 2 divisors, whose sum is σ = 1338394244. Its totient is φ = 1338394242.

The previous prime is 1338394177. The next prime is 1338394247. The reversal of 1338394243 is 3424938331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1338394243 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1338394196 and 1338394205.

It is not a weakly prime, because it can be changed into another prime (1338394247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 669197121 + 669197122.

It is an arithmetic number, because the mean of its divisors is an integer number (669197122).

Almost surely, 21338394243 is an apocalyptic number.

1338394243 is a deficient number, since it is larger than the sum of its proper divisors (1).

1338394243 is an equidigital number, since it uses as much as digits as its factorization.

1338394243 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 186624, while the sum is 40.

The square root of 1338394243 is about 36584.0708915779. The cubic root of 1338394243 is about 1102.0332210564.

The spelling of 1338394243 in words is "one billion, three hundred thirty-eight million, three hundred ninety-four thousand, two hundred forty-three".