Base | Representation |
---|---|
bin | 10011011111000010010… |
… | …001001101010100100011 |
3 | 11202000011210122222201202 |
4 | 103133002101031110203 |
5 | 133414224443314341 |
6 | 2503043030551415 |
7 | 165511344141344 |
oct | 23370221152443 |
9 | 4660153588652 |
10 | 1338994119971 |
11 | 476956300722 |
12 | 19760a50856b |
13 | 99360961301 |
14 | 48b443180cb |
15 | 24c6c46879b |
hex | 137c244d523 |
1338994119971 has 2 divisors, whose sum is σ = 1338994119972. Its totient is φ = 1338994119970.
The previous prime is 1338994119961. The next prime is 1338994120033. The reversal of 1338994119971 is 1799114998331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1338994119971 - 230 = 1337920378147 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1338994119898 and 1338994119907.
It is not a weakly prime, because it can be changed into another prime (1338994119961) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 669497059985 + 669497059986.
It is an arithmetic number, because the mean of its divisors is an integer number (669497059986).
Almost surely, 21338994119971 is an apocalyptic number.
1338994119971 is a deficient number, since it is larger than the sum of its proper divisors (1).
1338994119971 is an equidigital number, since it uses as much as digits as its factorization.
1338994119971 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13226976, while the sum is 65.
The spelling of 1338994119971 in words is "one trillion, three hundred thirty-eight billion, nine hundred ninety-four million, one hundred nineteen thousand, nine hundred seventy-one".
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