Base | Representation |
---|---|
bin | 10011011111001100011… |
… | …010101000000010111001 |
3 | 11202000121200000010100221 |
4 | 103133030122220002321 |
5 | 133420102034022024 |
6 | 2503111551500041 |
7 | 165515512152505 |
oct | 23371432500271 |
9 | 4660550003327 |
10 | 1339164360889 |
11 | 476a334081a3 |
12 | 197657527621 |
13 | 99389cc9194 |
14 | 48b5cb91305 |
15 | 24c7c3953e4 |
hex | 137cc6a80b9 |
1339164360889 has 2 divisors, whose sum is σ = 1339164360890. Its totient is φ = 1339164360888.
The previous prime is 1339164360857. The next prime is 1339164360901. The reversal of 1339164360889 is 9880634619331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1191503233600 + 147661127289 = 1091560^2 + 384267^2 .
It is a cyclic number.
It is not a de Polignac number, because 1339164360889 - 25 = 1339164360857 is a prime.
It is a super-2 number, since 2×13391643608892 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1339164360689) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 669582180444 + 669582180445.
It is an arithmetic number, because the mean of its divisors is an integer number (669582180445).
Almost surely, 21339164360889 is an apocalyptic number.
It is an amenable number.
1339164360889 is a deficient number, since it is larger than the sum of its proper divisors (1).
1339164360889 is an equidigital number, since it uses as much as digits as its factorization.
1339164360889 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20155392, while the sum is 61.
The spelling of 1339164360889 in words is "one trillion, three hundred thirty-nine billion, one hundred sixty-four million, three hundred sixty thousand, eight hundred eighty-nine".
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