Base | Representation |
---|---|
bin | 11000111100011100… |
… | …10111111010001101 |
3 | 1021120022101101121020 |
4 | 30132032113322031 |
5 | 204411322030232 |
6 | 10052512424353 |
7 | 652603001613 |
oct | 143616277215 |
9 | 37508341536 |
10 | 13391986317 |
11 | 5752477596 |
12 | 2718b480b9 |
13 | 1355668878 |
14 | 9108456b3 |
15 | 535a80e2c |
hex | 31e397e8d |
13391986317 has 24 divisors (see below), whose sum is σ = 19036937376. Its totient is φ = 8372329728.
The previous prime is 13391986271. The next prime is 13391986337. The reversal of 13391986317 is 71368919331.
It is not a de Polignac number, because 13391986317 - 26 = 13391986253 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a self number, because there is not a number n which added to its sum of digits gives 13391986317.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13391986337) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 212278 + ... + 268040.
It is an arithmetic number, because the mean of its divisors is an integer number (793205724).
Almost surely, 213391986317 is an apocalyptic number.
13391986317 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
13391986317 is a deficient number, since it is larger than the sum of its proper divisors (5644951059).
13391986317 is a wasteful number, since it uses less digits than its factorization.
13391986317 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56077 (or 56060 counting only the distinct ones).
The product of its digits is 734832, while the sum is 51.
The spelling of 13391986317 in words is "thirteen billion, three hundred ninety-one million, nine hundred eighty-six thousand, three hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.123 sec. • engine limits •