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133921565441 is a prime number
BaseRepresentation
bin111110010111001011…
…0001110101100000001
3110210200020001102002022
41330232112032230001
54143232410043231
6141304523531225
712450462344516
oct1745626165401
9423606042068
10133921565441
1151883261304
1221b56089b15
13c823493561
1466a624330d
15373c293c7b
hex1f2e58eb01

133921565441 has 2 divisors, whose sum is σ = 133921565442. Its totient is φ = 133921565440.

The previous prime is 133921565381. The next prime is 133921565467. The reversal of 133921565441 is 144565129331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133003172416 + 918393025 = 364696^2 + 30305^2 .

It is a cyclic number.

It is not a de Polignac number, because 133921565441 - 218 = 133921303297 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133921565392 and 133921565401.

It is not a weakly prime, because it can be changed into another prime (133921562441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66960782720 + 66960782721.

It is an arithmetic number, because the mean of its divisors is an integer number (66960782721).

Almost surely, 2133921565441 is an apocalyptic number.

It is an amenable number.

133921565441 is a deficient number, since it is larger than the sum of its proper divisors (1).

133921565441 is an equidigital number, since it uses as much as digits as its factorization.

133921565441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 388800, while the sum is 44.

The spelling of 133921565441 in words is "one hundred thirty-three billion, nine hundred twenty-one million, five hundred sixty-five thousand, four hundred forty-one".