1340001433 has 2 divisors, whose sum is σ = 1340001434. Its totient is φ = 1340001432.

The previous prime is 1340001427. The next prime is 1340001493. The reversal of 1340001433 is 3341000431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1153077849 + 186923584 = 33957^2 + 13672^2 .

It is an emirp because it is prime and its reverse (3341000431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340001433 - 2¹³ = 1339993241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1340001433.

It is not a weakly prime, because it can be changed into another prime (1340001493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670000716 + 670000717.

It is an arithmetic number, because the mean of its divisors is an integer number (670000717).

Almost surely, 2^1340001433 is an apocalyptic number.

It is an amenable number.

1340001433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340001433 is an equidigital number, since it uses as much as digits as its factorization.

1340001433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 1340001433 is about 36606.0300087294. The cubic root of 1340001433 is about 1102.4741644458.

Adding to 1340001433 its reverse (3341000431), we get a palindrome (4681001864).

The spelling of 1340001433 in words is "one billion, three hundred forty million, one thousand, four hundred thirty-three".