13400020101019 has 2 divisors, whose sum is σ = 13400020101020. Its totient is φ = 13400020101018.

The previous prime is 13400020100981. The next prime is 13400020101079. The reversal of 13400020101019 is 91010102000431.

It is a weak prime.

It is an emirp because it is prime and its reverse (91010102000431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13400020101019 - 2¹³ = 13400020092827 is a prime.

It is a super-3 number, since 3×13400020101019³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (13400020101079) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700010050509 + 6700010050510.

It is an arithmetic number, because the mean of its divisors is an integer number (6700010050510).

Almost surely, 2^{13400020101019} is an apocalyptic number.

13400020101019 is a deficient number, since it is larger than the sum of its proper divisors (1).

13400020101019 is an equidigital number, since it uses as much as digits as its factorization.

13400020101019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 22.

The spelling of 13400020101019 in words is "thirteen trillion, four hundred billion, twenty million, one hundred one thousand, nineteen".