Base | Representation |
---|---|
bin | 1100001011111111000000… |
… | …0011110100101110111111 |
3 | 1202110000211011112000020101 |
4 | 3002333300003310232333 |
5 | 3224021230303433440 |
6 | 44255520011101531 |
7 | 2552056151120530 |
oct | 302776003645677 |
9 | 52400734460211 |
10 | 13400030530495 |
11 | 42a6a14995104 |
12 | 16050231418a7 |
13 | 76280472602b |
14 | 3447ca294687 |
15 | 183873ab169a |
hex | c2ff00f4bbf |
13400030530495 has 32 divisors (see below), whose sum is σ = 19176710879232. Its totient is φ = 8788850877312.
The previous prime is 13400030530409. The next prime is 13400030530511. The reversal of 13400030530495 is 59403503000431.
It is a cyclic number.
It is not a de Polignac number, because 13400030530495 - 213 = 13400030522303 is a prime.
It is a super-2 number, since 2×134000305304952 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 32553334 + ... + 32962396.
It is an arithmetic number, because the mean of its divisors is an integer number (599272214976).
Almost surely, 213400030530495 is an apocalyptic number.
13400030530495 is a deficient number, since it is larger than the sum of its proper divisors (5776680348737).
13400030530495 is a wasteful number, since it uses less digits than its factorization.
13400030530495 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 449791.
The product of its (nonzero) digits is 97200, while the sum is 37.
The spelling of 13400030530495 in words is "thirteen trillion, four hundred billion, thirty million, five hundred thirty thousand, four hundred ninety-five".
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