Base | Representation |
---|---|
bin | 1100001011111111000000… |
… | …0011110100101111111011 |
3 | 1202110000211011112000022121 |
4 | 3002333300003310233323 |
5 | 3224021230303434210 |
6 | 44255520011102111 |
7 | 2552056151120644 |
oct | 302776003645773 |
9 | 52400734460277 |
10 | 13400030530555 |
11 | 42a6a14995159 |
12 | 1605023141937 |
13 | 762804726076 |
14 | 3447ca2946cb |
15 | 183873ab16da |
hex | c2ff00f4bfb |
13400030530555 has 16 divisors (see below), whose sum is σ = 16988446638720. Its totient is φ = 10130147800192.
The previous prime is 13400030530511. The next prime is 13400030530559. The reversal of 13400030530555 is 55503503000431.
It is a cyclic number.
It is not a de Polignac number, because 13400030530555 - 215 = 13400030497787 is a prime.
It is a super-2 number, since 2×134000305305552 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13400030530555.
It is not an unprimeable number, because it can be changed into a prime (13400030530559) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 983120884 + ... + 983134513.
It is an arithmetic number, because the mean of its divisors is an integer number (1061777914920).
Almost surely, 213400030530555 is an apocalyptic number.
13400030530555 is a deficient number, since it is larger than the sum of its proper divisors (3588416108165).
13400030530555 is a wasteful number, since it uses less digits than its factorization.
13400030530555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1966255478.
The product of its (nonzero) digits is 67500, while the sum is 34.
Adding to 13400030530555 its reverse (55503503000431), we get a palindrome (68903533530986).
The spelling of 13400030530555 in words is "thirteen trillion, four hundred billion, thirty million, five hundred thirty thousand, five hundred fifty-five".
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