13400042003 has 2 divisors, whose sum is σ = 13400042004. Its totient is φ = 13400042002.

The previous prime is 13400041999. The next prime is 13400042017. The reversal of 13400042003 is 30024000431.

13400042003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13400042003 - 2² = 13400041999 is a prime.

It is a super-2 number, since 2×13400042003² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13400042023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700021001 + 6700021002.

It is an arithmetic number, because the mean of its divisors is an integer number (6700021002).

Almost surely, 2^13400042003 is an apocalyptic number.

13400042003 is a deficient number, since it is larger than the sum of its proper divisors (1).

13400042003 is an equidigital number, since it uses as much as digits as its factorization.

13400042003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 17.

Adding to 13400042003 its reverse (30024000431), we get a palindrome (43424042434).

The spelling of 13400042003 in words is "thirteen billion, four hundred million, forty-two thousand, three".