Base | Representation |
---|---|
bin | 10011011111111110011… |
… | …110100000110000011011 |
3 | 11202002210012101102110220 |
4 | 103133332132200300123 |
5 | 133423312041143121 |
6 | 2503331153211123 |
7 | 165545361053034 |
oct | 23377636406033 |
9 | 4662705342426 |
10 | 1340004240411 |
11 | 477324507101 |
12 | 197850860aa3 |
13 | 99492002b05 |
14 | 48bdc53ba8b |
15 | 24ccae986c6 |
hex | 137fe7a0c1b |
1340004240411 has 16 divisors (see below), whose sum is σ = 1891214467200. Its totient is φ = 841590425088.
The previous prime is 1340004240403. The next prime is 1340004240437. The reversal of 1340004240411 is 1140424000431.
It is not a de Polignac number, because 1340004240411 - 23 = 1340004240403 is a prime.
It is a super-2 number, since 2×13400042404112 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1340004240811) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 65656966 + ... + 65677371.
It is an arithmetic number, because the mean of its divisors is an integer number (118200904200).
Almost surely, 21340004240411 is an apocalyptic number.
1340004240411 is a deficient number, since it is larger than the sum of its proper divisors (551210226789).
1340004240411 is a wasteful number, since it uses less digits than its factorization.
1340004240411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131334538.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 1340004240411 its reverse (1140424000431), we get a palindrome (2480428240842).
The spelling of 1340004240411 in words is "one trillion, three hundred forty billion, four million, two hundred forty thousand, four hundred eleven".
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