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1340004240412 = 221073130851029
BaseRepresentation
bin10011011111111110011…
…110100000110000011100
311202002210012101102110221
4103133332132200300130
5133423312041143122
62503331153211124
7165545361053035
oct23377636406034
94662705342427
101340004240412
11477324507102
12197850860aa4
1399492002b06
1448bdc53ba8c
1524ccae986c7
hex137fe7a0c1c

1340004240412 has 12 divisors (see below), whose sum is σ = 2366923378680. Its totient is φ = 663740417936.

The previous prime is 1340004240403. The next prime is 1340004240437. The reversal of 1340004240412 is 2140424000431.

It is a super-2 number, since 2×13400042404122 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1565425087 + ... + 1565425942.

It is an arithmetic number, because the mean of its divisors is an integer number (197243614890).

Almost surely, 21340004240412 is an apocalyptic number.

It is an amenable number.

1340004240412 is a deficient number, since it is larger than the sum of its proper divisors (1026919138268).

1340004240412 is a wasteful number, since it uses less digits than its factorization.

1340004240412 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3130851140 (or 3130851138 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 1340004240412 its reverse (2140424000431), we get a palindrome (3480428240843).

The spelling of 1340004240412 in words is "one trillion, three hundred forty billion, four million, two hundred forty thousand, four hundred twelve".

Divisors: 1 2 4 107 214 428 3130851029 6261702058 12523404116 335001060103 670002120206 1340004240412