Base | Representation |
---|---|
bin | 1100001011111111000011… |
… | …0111111110000100001011 |
3 | 1202110000212010020111112212 |
4 | 3002333300313332010023 |
5 | 3224021242303401303 |
6 | 44255521220055335 |
7 | 2552056405243103 |
oct | 302776067760413 |
9 | 52400763214485 |
10 | 13400044200203 |
11 | 42a6a21681391 |
12 | 160502783454b |
13 | 76280750100b |
14 | 3447cc012203 |
15 | 183874db1ad8 |
hex | c2ff0dfe10b |
13400044200203 has 2 divisors, whose sum is σ = 13400044200204. Its totient is φ = 13400044200202.
The previous prime is 13400044200167. The next prime is 13400044200247. The reversal of 13400044200203 is 30200244000431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13400044200203 - 218 = 13400043938059 is a prime.
It is a super-2 number, since 2×134000442002032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13400044208203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700022100101 + 6700022100102.
It is an arithmetic number, because the mean of its divisors is an integer number (6700022100102).
Almost surely, 213400044200203 is an apocalyptic number.
13400044200203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13400044200203 is an equidigital number, since it uses as much as digits as its factorization.
13400044200203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 13400044200203 its reverse (30200244000431), we get a palindrome (43600288200634).
The spelling of 13400044200203 in words is "thirteen trillion, four hundred billion, forty-four million, two hundred thousand, two hundred three".
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