Base | Representation |
---|---|
bin | 111110011001100001… |
… | …1011000101101110111 |
3 | 110210212201121022012212 |
4 | 1330303003120231313 |
5 | 4143413112334423 |
6 | 141320424004035 |
7 | 12452441362151 |
oct | 1746303305567 |
9 | 423781538185 |
10 | 134000511863 |
11 | 51913882989 |
12 | 21b7860061b |
13 | c83694520a |
14 | 66b2913ad1 |
15 | 374418a578 |
hex | 1f330d8b77 |
134000511863 has 4 divisors (see below), whose sum is σ = 135887843088. Its totient is φ = 132113180640.
The previous prime is 134000511857. The next prime is 134000511889. The reversal of 134000511863 is 368115000431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 368115000431 = 1409 ⋅261259759.
It is a cyclic number.
It is not a de Polignac number, because 134000511863 - 232 = 129705544567 is a prime.
It is a super-2 number, since 2×1340005118632 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134000511893) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 943665506 + ... + 943665647.
It is an arithmetic number, because the mean of its divisors is an integer number (33971960772).
Almost surely, 2134000511863 is an apocalyptic number.
134000511863 is a deficient number, since it is larger than the sum of its proper divisors (1887331225).
134000511863 is an equidigital number, since it uses as much as digits as its factorization.
134000511863 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1887331224.
The product of its (nonzero) digits is 8640, while the sum is 32.
The spelling of 134000511863 in words is "one hundred thirty-four billion, five hundred eleven thousand, eight hundred sixty-three".
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