1340012201353 has 4 divisors (see below), whose sum is σ = 1531442515840. Its totient is φ = 1148581886868.

The previous prime is 1340012201299. The next prime is 1340012201417. The reversal of 1340012201353 is 3531022100431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340012201353 - 2¹³ = 1340012193161 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340012201153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95715157233 + ... + 95715157246.

It is an arithmetic number, because the mean of its divisors is an integer number (382860628960).

Almost surely, 2^{1340012201353} is an apocalyptic number.

It is an amenable number.

1340012201353 is a deficient number, since it is larger than the sum of its proper divisors (191430314487).

1340012201353 is an equidigital number, since it uses as much as digits as its factorization.

1340012201353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191430314486.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 1340012201353 its reverse (3531022100431), we get a palindrome (4871034301784).

The spelling of 1340012201353 in words is "one trillion, three hundred forty billion, twelve million, two hundred one thousand, three hundred fifty-three".