134001443413141 has 4 divisors (see below), whose sum is σ = 134776018230732. Its totient is φ = 133226868595552.

The previous prime is 134001443413133. The next prime is 134001443413163. The reversal of 134001443413141 is 141314344100431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 92220086590641 + 41781356822500 = 9603129^2 + 6463850^2 .

It is a cyclic number.

It is not a de Polignac number, because 134001443413141 - 2³ = 134001443413133 is a prime.

It is a super-2 number, since 2×134001443413141² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134001443413097 and 134001443413106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134001443413171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 387287408536 + ... + 387287408881.

It is an arithmetic number, because the mean of its divisors is an integer number (33694004557683).

Almost surely, 2^{134001443413141} is an apocalyptic number.

It is an amenable number.

134001443413141 is a deficient number, since it is larger than the sum of its proper divisors (774574817591).

134001443413141 is an equidigital number, since it uses as much as digits as its factorization.

134001443413141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 774574817590.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 134001443413141 its reverse (141314344100431), we get a palindrome (275315787513572).

The spelling of 134001443413141 in words is "one hundred thirty-four trillion, one billion, four hundred forty-three million, four hundred thirteen thousand, one hundred forty-one".