Base | Representation |
---|---|
bin | 11110011110000000101000… |
… | …111011011010111000001111 |
3 | 122120110121212220111100101211 |
4 | 132132000220323122320033 |
5 | 120031004002033103211 |
6 | 1153000233501315251 |
7 | 40140305525564254 |
oct | 3636005073327017 |
9 | 576417786440354 |
10 | 134003666300431 |
11 | 397746aa181654 |
12 | 13042984865b27 |
13 | 59a0650b05655 |
14 | 2513b523c942b |
15 | 1075b2235ee21 |
hex | 79e028edae0f |
134003666300431 has 4 divisors (see below), whose sum is σ = 134004024236664. Its totient is φ = 134003308364200.
The previous prime is 134003666300423. The next prime is 134003666300443.
134003666300431 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134003666300431 - 23 = 134003666300423 is a prime.
It is a super-2 number, since 2×1340036663004312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134003666307431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 178405960 + ... + 179155501.
It is an arithmetic number, because the mean of its divisors is an integer number (33501006059166).
Almost surely, 2134003666300431 is an apocalyptic number.
134003666300431 is a deficient number, since it is larger than the sum of its proper divisors (357936233).
134003666300431 is an equidigital number, since it uses as much as digits as its factorization.
134003666300431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 357936232.
The product of its (nonzero) digits is 279936, while the sum is 40.
The spelling of 134003666300431 in words is "one hundred thirty-four trillion, three billion, six hundred sixty-six million, three hundred thousand, four hundred thirty-one".
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