Base | Representation |
---|---|
bin | 11110011110000000101000… |
… | …111011011010111000000111 |
3 | 122120110121212220111100101112 |
4 | 132132000220323122320013 |
5 | 120031004002033103143 |
6 | 1153000233501315235 |
7 | 40140305525564243 |
oct | 3636005073327007 |
9 | 576417786440345 |
10 | 134003666300423 |
11 | 397746aa181647 |
12 | 13042984865b1b |
13 | 59a0650b0564a |
14 | 2513b523c9423 |
15 | 1075b2235ee18 |
hex | 79e028edae07 |
134003666300423 has 2 divisors, whose sum is σ = 134003666300424. Its totient is φ = 134003666300422.
The previous prime is 134003666300407. The next prime is 134003666300443. The reversal of 134003666300423 is 324003666300431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134003666300423 - 24 = 134003666300407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134003666300443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67001833150211 + 67001833150212.
It is an arithmetic number, because the mean of its divisors is an integer number (67001833150212).
Almost surely, 2134003666300423 is an apocalyptic number.
134003666300423 is a deficient number, since it is larger than the sum of its proper divisors (1).
134003666300423 is an equidigital number, since it uses as much as digits as its factorization.
134003666300423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 41.
The spelling of 134003666300423 in words is "one hundred thirty-four trillion, three billion, six hundred sixty-six million, three hundred thousand, four hundred twenty-three".
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