Base | Representation |
---|---|
bin | 1100001100000000011000… |
… | …0110111000011110011010 |
3 | 1202110001202221112220100011 |
4 | 3003000012012320132122 |
5 | 3224023010002243002 |
6 | 44300020423232134 |
7 | 2552101262200624 |
oct | 303000606703632 |
9 | 52401687486304 |
10 | 13400400431002 |
11 | 42a7094771902 |
12 | 1605106ba864a |
13 | 762863259280 |
14 | 344823461c14 |
15 | 1838962cb8d7 |
hex | c30061b879a |
13400400431002 has 32 divisors (see below), whose sum is σ = 21761338959360. Its totient is φ = 6152107187520.
The previous prime is 13400400430999. The next prime is 13400400431027. The reversal of 13400400431002 is 20013400400431.
It is a super-2 number, since 2×134004004310022 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9331024 + ... + 10670932.
It is an arithmetic number, because the mean of its divisors is an integer number (680041842480).
Almost surely, 213400400431002 is an apocalyptic number.
13400400431002 is a deficient number, since it is larger than the sum of its proper divisors (8360938528358).
13400400431002 is a wasteful number, since it uses less digits than its factorization.
13400400431002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1341958.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 13400400431002 its reverse (20013400400431), we get a palindrome (33413800831433).
The spelling of 13400400431002 in words is "thirteen trillion, four hundred billion, four hundred million, four hundred thirty-one thousand, two".
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