13400402020 has 48 divisors (see below), whose sum is σ = 28252820736. Its totient is φ = 5338880000.

The previous prime is 13400402011. The next prime is 13400402021. The reversal of 13400402020 is 2020400431.

It is a junction number, because it is equal to n+sod(n) for n = 13400401985 and 13400402003.

It is not an unprimeable number, because it can be changed into a prime (13400402021) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8369220 + ... + 8370820.

It is an arithmetic number, because the mean of its divisors is an integer number (588600432).

Almost surely, 2^13400402020 is an apocalyptic number.

13400402020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13400402020 is an abundant number, since it is smaller than the sum of its proper divisors (14852418716).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13400402020 is a wasteful number, since it uses less digits than its factorization.

13400402020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3012 (or 3010 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 16.

Adding to 13400402020 its reverse (2020400431), we get a palindrome (15420802451).

The spelling of 13400402020 in words is "thirteen billion, four hundred million, four hundred two thousand, twenty".