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134004154506203 = 294620832914007
BaseRepresentation
bin11110011110000001000110…
…000001110001101111011011
3122120110200010221010202211002
4132132001012001301233123
5120031011002023144303
61153000354141255215
740140323604346562
oct3636010601615733
9576420127122732
10134004154506203
113977492a8128a3
1213042aa026450b
1359a06cacbb2c7
142513b9b190bd9
151075b50148788
hex79e046071bdb

134004154506203 has 4 divisors (see below), whose sum is σ = 138624987420240. Its totient is φ = 129383321592168.

The previous prime is 134004154506161. The next prime is 134004154506223. The reversal of 134004154506203 is 302605451400431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134004154506203 - 220 = 134004153457627 is a prime.

It is a super-2 number, since 2×1340041545062032 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134004154506223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2310416456975 + ... + 2310416457032.

It is an arithmetic number, because the mean of its divisors is an integer number (34656246855060).

Almost surely, 2134004154506203 is an apocalyptic number.

134004154506203 is a deficient number, since it is larger than the sum of its proper divisors (4620832914037).

134004154506203 is an equidigital number, since it uses as much as digits as its factorization.

134004154506203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4620832914036.

The product of its (nonzero) digits is 172800, while the sum is 38.

The spelling of 134004154506203 in words is "one hundred thirty-four trillion, four billion, one hundred fifty-four million, five hundred six thousand, two hundred three".

Divisors: 1 29 4620832914007 134004154506203