Base | Representation |
---|---|
bin | 11110011110000001000110… |
… | …000001110001101111101111 |
3 | 122120110200010221010202211211 |
4 | 132132001012001301233233 |
5 | 120031011002023144343 |
6 | 1153000354141255251 |
7 | 40140323604346621 |
oct | 3636010601615757 |
9 | 576420127122754 |
10 | 134004154506223 |
11 | 3977492a812911 |
12 | 13042aa0264527 |
13 | 59a06cacbb311 |
14 | 2513b9b190c11 |
15 | 1075b5014879d |
hex | 79e046071bef |
134004154506223 has 2 divisors, whose sum is σ = 134004154506224. Its totient is φ = 134004154506222.
The previous prime is 134004154506161. The next prime is 134004154506241. The reversal of 134004154506223 is 322605451400431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134004154506223 - 213 = 134004154498031 is a prime.
It is a super-2 number, since 2×1340041545062232 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134004154506253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67002077253111 + 67002077253112.
It is an arithmetic number, because the mean of its divisors is an integer number (67002077253112).
Almost surely, 2134004154506223 is an apocalyptic number.
134004154506223 is a deficient number, since it is larger than the sum of its proper divisors (1).
134004154506223 is an equidigital number, since it uses as much as digits as its factorization.
134004154506223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 345600, while the sum is 40.
The spelling of 134004154506223 in words is "one hundred thirty-four trillion, four billion, one hundred fifty-four million, five hundred six thousand, two hundred twenty-three".
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