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134005211 is a prime number
BaseRepresentation
bin1111111110011…
…00000111011011
3100100011011120222
413333030013123
5233301131321
621144110255
73215011514
oct777140733
9310134528
10134005211
116970810a
1238a6538b
13219bb832
1413b23a0b
15bb703ab
hex7fcc1db

134005211 has 2 divisors, whose sum is σ = 134005212. Its totient is φ = 134005210.

The previous prime is 134005177. The next prime is 134005217. The reversal of 134005211 is 112500431.

It is a strong prime.

It is an emirp because it is prime and its reverse (112500431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134005211 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134005211.

It is not a weakly prime, because it can be changed into another prime (134005217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67002605 + 67002606.

It is an arithmetic number, because the mean of its divisors is an integer number (67002606).

Almost surely, 2134005211 is an apocalyptic number.

134005211 is a deficient number, since it is larger than the sum of its proper divisors (1).

134005211 is an equidigital number, since it uses as much as digits as its factorization.

134005211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 134005211 is about 11576.0619815203. The cubic root of 134005211 is about 511.7296279100.

Adding to 134005211 its reverse (112500431), we get a palindrome (246505642).

The spelling of 134005211 in words is "one hundred thirty-four million, five thousand, two hundred eleven".