Base | Representation |
---|---|
bin | 11110011110000010010110… |
… | …111110001000001011100010 |
3 | 122120110210122120110012122001 |
4 | 132132002112332020023202 |
5 | 120031021242200112114 |
6 | 1153001141012034214 |
7 | 40140402344215123 |
oct | 3636022676101342 |
9 | 576423576405561 |
10 | 134005512504034 |
11 | 39775467323756 |
12 | 130431bb00296a |
13 | 59a0886451b12 |
14 | 2513c8968c04a |
15 | 1075bce493374 |
hex | 79e096f882e2 |
134005512504034 has 8 divisors (see below), whose sum is σ = 204303486276828. Its totient is φ = 65904350411760.
The previous prime is 134005512503999. The next prime is 134005512504037. The reversal of 134005512504034 is 430405215500431.
It can be written as a sum of positive squares in 2 ways, for example, as 103209283684809 + 30796228819225 = 10159197^2 + 5549435^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 134005512503984 and 134005512504002.
It is not an unprimeable number, because it can be changed into a prime (134005512504037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 549202919977 + ... + 549202920220.
Almost surely, 2134005512504034 is an apocalyptic number.
134005512504034 is a deficient number, since it is larger than the sum of its proper divisors (70297973772794).
134005512504034 is a wasteful number, since it uses less digits than its factorization.
134005512504034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1098405840260.
The product of its (nonzero) digits is 144000, while the sum is 37.
The spelling of 134005512504034 in words is "one hundred thirty-four trillion, five billion, five hundred twelve million, five hundred four thousand, thirty-four".
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