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134005512504034 = 2611098405840197
BaseRepresentation
bin11110011110000010010110…
…111110001000001011100010
3122120110210122120110012122001
4132132002112332020023202
5120031021242200112114
61153001141012034214
740140402344215123
oct3636022676101342
9576423576405561
10134005512504034
1139775467323756
12130431bb00296a
1359a0886451b12
142513c8968c04a
151075bce493374
hex79e096f882e2

134005512504034 has 8 divisors (see below), whose sum is σ = 204303486276828. Its totient is φ = 65904350411760.

The previous prime is 134005512503999. The next prime is 134005512504037. The reversal of 134005512504034 is 430405215500431.

It can be written as a sum of positive squares in 2 ways, for example, as 103209283684809 + 30796228819225 = 10159197^2 + 5549435^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 134005512503984 and 134005512504002.

It is not an unprimeable number, because it can be changed into a prime (134005512504037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 549202919977 + ... + 549202920220.

Almost surely, 2134005512504034 is an apocalyptic number.

134005512504034 is a deficient number, since it is larger than the sum of its proper divisors (70297973772794).

134005512504034 is a wasteful number, since it uses less digits than its factorization.

134005512504034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1098405840260.

The product of its (nonzero) digits is 144000, while the sum is 37.

The spelling of 134005512504034 in words is "one hundred thirty-four trillion, five billion, five hundred twelve million, five hundred four thousand, thirty-four".

Divisors: 1 2 61 122 1098405840197 2196811680394 67002756252017 134005512504034